3x^2+5x=(3x+1)(x-2)

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Solution for 3x^2+5x=(3x+1)(x-2) equation: 



3x^2+5x=(3x+1)(x-2)

We move all terms to the left:

3x^2+5x-((3x+1)(x-2))=0

We multiply parentheses ..

3x^2-((+3x^2-6x+x-2))+5x=0



We calculate terms in parentheses: -((+3x^2-6x+x-2)), so:

(+3x^2-6x+x-2)

We get rid of parentheses

3x^2-6x+x-2

We add all the numbers together, and all the variables

3x^2-5x-2

Back to the equation:

-(3x^2-5x-2)



We add all the numbers together, and all the variables

3x^2+5x-(3x^2-5x-2)=0

We get rid of parentheses

3x^2-3x^2+5x+5x+2=0

We add all the numbers together, and all the variables

10x+2=0

We move all terms containing x to the left, all other terms to the right

10x=-2

x=-2/10

x=-1/5

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